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4.9x^2+7.99x-45=0
a = 4.9; b = 7.99; c = -45;
Δ = b2-4ac
Δ = 7.992-4·4.9·(-45)
Δ = 945.8401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.99)-\sqrt{945.8401}}{2*4.9}=\frac{-7.99-\sqrt{945.8401}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.99)+\sqrt{945.8401}}{2*4.9}=\frac{-7.99+\sqrt{945.8401}}{9.8} $
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